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Description Estimate the zeros of the function shown in the graph below. {­-2.9, ­-1, 0.8} {-­ ...


Description Estimate the zeros of the function shown in the graph below. {­-2.9, ­-1, 0.8} {-­2, 0} {-­2, ­-1, 0} {­-2.9, -­1, ­-2, 0.8 ========================= In the function shown in the chart below, at which values of x are there relative minima or maxima? x f(x) -3 -2 -2 2 -1 0 0 -2 1 2 2 18 3 52 2 and ­-2 -3 and 3 -2 and 0 -3, 0, and 3 ============================ In the function shown in the chart below, between what values of x would you find the zeros of the function? x f(x) -3 73 -2 8 -1 -7 0 -8 1 -7 2 8 3 73 -1 and 0, 0 and 1 -2 and ­-1, 1 and 2 -7 and 8, ­-8 and ­-7 1 and ­-1 ============================ Which of the following could be the graph of f(x) = x3 + x2 ­- 3x? A. B. C. D. ======== ======================================== Estimate the relative maximums in the graph below. (1.3, 1.4) and (-­0.6, 2.6) (­-0.6, 2.6,), (0.5, 0.3), and (1.3, 1.4) (­-1, 0) and (1.8, 0) (-­1, 0), (0, 1), and (1.8, 0) ==================== Which of the following shows a graph that meets the following conditions. I. As x ? ?, f(x) ? ? II. The degree of f(x) is odd III. the leading coefficient is positive A. B. C. D. ===================================== For the graph below, which of the following is true? I. As x ? ?, f(x) ? ? II. As x ? ?, f(x) ? ­-? III. As x ? -­?, f(x) ? ? IV. As x ? ­-?, f(x) ? -­? V. f(x) is odd VI. the leading coefficient is negative I, III, and V are true II, III, V, and VI are true II, III, and V are true II, IV, V, and VI are true ==================================== Find r(x + 1) if r(x) = x3 + x + 1 x3 + 3x2 + 4x + 3 x3 + 4x2 + 5x + 3 x3 + 2x + 3 x4 + x3 + x2 + 2x + 1 ======================= Find p(­-4) if p(x) = x5 - x2 1040 -1040 1008 -1008 ============================ What is the degree and leading coefficient of the polynomial below? 6x3 + 3x4 = 2x2 - 2 degree = 4, leading coefficient = 3 degree = 3, leading coefficient = 6 degree = 2, leading coefficient = 2 degree = 0, leading coefficient = ­-2



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